JPA Criteria-Abfrage Weg.Holen Sie left join ist es möglich

Ich habe eine Frage bezüglich der JPA-Kriterien.

Hier ist mein JPA criteria-Abfrage:

 CriteriaBuilder criteriaBuilder = getEm().getCriteriaBuilder();
 CriteriaQuery<InventoryItemSumReport> query = criteriaBuilder.createQuery(InventoryItemSumReport.class);
 Root<InventoryItemDetail> from = query.from(InventoryItemDetail.class);    

 Join<InventoryItemDetail, InventoryItem> joinItem = from.join(InventoryItemDetail_.inventoryItem); 

 Predicate where = criteriaBuilder.lessThanOrEqualTo(from.get(InventoryItemDetail_.effectiveDate), date);

 query.multiselect(joinItem.get(InventoryItem_.product),joinItem.get(InventoryItem_.facility),joinItem.get(InventoryItem_.customer));
 query.groupBy(joinItem.get(InventoryItem_.product),joinItem.get(InventoryItem_.facility),joinItem.get(InventoryItem_.customer));
 query.where(where); 

 TypedQuery<InventoryItemSumReport> createQuery = getEm().createQuery(query);       
 List<InventoryItemSumReport> resultList = createQuery.getResultList();

Hier ist die resultierende Abfrage produziert von JPA-provider:

    select
        inventoryi1_.PRODUCT_ID as col_0_0_,
        inventoryi1_.FACILITY_ID as col_1_0_,
        inventoryi1_.CUSTOMER_ID as col_2_0_ 
    from
        INVENTORY_ITEM_DETAIL inventoryi0_ 
    inner join
        INVENTORY_ITEM inventoryi1_ 
            on inventoryi0_.INVENTORY_ITEM_ID=inventoryi1_.ID 
    inner join
        PRODUCT product2_ 
            on inventoryi1_.PRODUCT_ID=product2_.ID 
    inner join
        FACILITY facility3_ 
            on inventoryi1_.FACILITY_ID=facility3_.ID 
    inner join
        CUSTOMER customer4_ 
            on inventoryi1_.CUSTOMER_ID=customer4_.ID 
    where
        inventoryi0_.EFFECTIVE_DATE<= ? 
    group by
        inventoryi1_.PRODUCT_ID ,
        inventoryi1_.FACILITY_ID ,
        inventoryi1_.CUSTOMER_ID

Aber ich möchte die folgende Abfrage:

    select
        inventoryi1_.PRODUCT_ID as col_0_0_,
        inventoryi1_.FACILITY_ID as col_1_0_,
        inventoryi1_.CUSTOMER_ID as col_2_0_ 
    from
        INVENTORY_ITEM_DETAIL inventoryi0_ 
    inner join
        INVENTORY_ITEM inventoryi1_ 
            on inventoryi0_.INVENTORY_ITEM_ID=inventoryi1_.ID 
    inner join
        PRODUCT product2_ 
            on inventoryi1_.PRODUCT_ID=product2_.ID 
    inner join
        FACILITY facility3_ 
            on inventoryi1_.FACILITY_ID=facility3_.ID 
    left join
        CUSTOMER customer4_ 
            on inventoryi1_.CUSTOMER_ID=customer4_.ID 
    where
        inventoryi0_.EFFECTIVE_DATE<= ?
    group by
        inventoryi1_.PRODUCT_ID ,
        inventoryi1_.FACILITY_ID ,
        inventoryi1_.CUSTOMER_ID

mit einem left join KUNDE man auch Ergebnisse, wo Customers null sind.

Customer, Product, Facility sind alle entites, während InventoryItemSumReport ist ein Value-Objekt oder DTO.

public class InventoryItemSumReport implements Serializable {

   private static final long serialVersionUID = 1L;

   private Product product;
   private Facility facility;
   private Customer customer;

   public InventoryItemSumReport(Product product, Facility facility, Customer customer) {
       super();
       this.product = product;
       this.facility = facility;
       this.customer = customer;
   }
}
InformationsquelleAutor landal79 | 2012-04-13
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