server tomcat-v8.0 server at localhost konnte nicht gestartet werden

Ich glaube, ich habe ein problem mit meinem web.xml Datei.
jedes mal, wenn ich den Apache tomcat 8-server, gibt es diese Fehlermeldung:
server tomcat-v8.0 server at localhost konnte nicht gestartet werden.

wenn ich entfernt die servlets, die xml-Datei, der server hat funktioniert!!
meine web.xml ist wie folgt:

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" version="2.5">
  <display-name>ZiyadA00191914</display-name>


  <servlet>
    <servlet-name>RegisterServlet</servlet-name>
    <servlet-class>controllers.RegisterServlet</servlet-class>
  </servlet>

<servlet-mapping>
    <servlet-name>RegisterServlet</servlet-name>
    <url-pattern>/RegisterServlet</url-pattern>
  </servlet-mapping>

  <servlet>
    <servlet-name>LoginServlet</servlet-name>
    <servlet-class>controllers.LoginServlet</servlet-class>
  </servlet>

<servlet-mapping>
    <servlet-name>LoginServlet</servlet-name>
    <url-pattern>/LoginServlet</url-pattern>
  </servlet-mapping>

    <servlet>
    <servlet-name>ListEventMainServlet</servlet-name>
    <servlet-class>controllers.ListEventMainServlet</servlet-class>
  </servlet>

<servlet-mapping>
    <servlet-name>ListEventMainServlet</servlet-name>
    <url-pattern>/ListEventMainServlet</url-pattern>
  </servlet-mapping>

    <servlet>
    <servlet-name>ListEventByCategory</servlet-name>
    <servlet-class>controllers.ListEventByCategory</servlet-class>
  </servlet>

<servlet-mapping>
    <servlet-name>ListEventByCategory</servlet-name>
    <url-pattern>/ListEventByCategory</url-pattern>
  </servlet-mapping>


  <servlet>
    <servlet-name>CartServlet</servlet-name>
    <servlet-class>controllers.CartServlet</servlet-class>
  </servlet>

<servlet-mapping>
    <servlet-name>CartServlet</servlet-name>
    <url-pattern>/CartServlet</url-pattern>
  </servlet-mapping>

    <servlet>
    <servlet-name>OrderServlet</servlet-name>
    <servlet-class>controllers.OrderServlet</servlet-class>
  </servlet>

<servlet-mapping>
    <servlet-name>OrderServlet</servlet-name>
    <url-pattern>/OrderServlet</url-pattern>
  </servlet-mapping>

  <servlet>
    <servlet-name>FeedbackServlet</servlet-name>
    <servlet-class>controllers.FeedbackServlet</servlet-class>
  </servlet>

<servlet-mapping>
    <servlet-name>FeedbackServlet</servlet-name>
    <url-pattern>/FeedbackServlet</url-pattern>
  </servlet-mapping>

    <servlet>
    <servlet-name>ShippingServlet</servlet-name>
    <servlet-class>controllers.ShippingServlet</servlet-class>
  </servlet>

<servlet-mapping>
    <servlet-name>ShippingServlet</servlet-name>
    <url-pattern>/ShippingServlet</url-pattern>
  </servlet-mapping>


  <servlet>
    <servlet-name>LogoutServlet</servlet-name>
    <servlet-class>controllers.LogoutServlet</servlet-class>
  </servlet>

<servlet-mapping>
    <servlet-name>LogoutServlet</servlet-name>
    <url-pattern>/LogoutServlet</url-pattern>
  </servlet-mapping>


  <welcome-file-list>
    <welcome-file>Driver.jsp</welcome-file>
    <welcome-file>index.jsp</welcome-file>
    <welcome-file>main.jsp</welcome-file>
    <welcome-file>listEvents.jsp</welcome-file>
  </welcome-file-list>
</web-app>

jede Anregung, um es zu bekommen Arbeit, ohne code von der xml-Datei ?

Vielen Dank im Voraus Jungs.

InformationsquelleAutor Ziyad M | 2016-04-20