Wie Bild aus lokalen Pfad aus jsp

Ich bin versucht, ein Bild anzuzeigen, werfen jsp. Bild ist gespeichert in den lokalen Pfad, also schrieb ich ein servlet get-Methode ermittelt werden Bild-und im src-Attribut des image-tag gebe ich dem servlet-Namen und Bild-Pfad als parameter an Servlets und hier ist mein code,

public class FileServlet extends HttpServlet {
private static final long serialVersionUID = 1L;

private static final int DEFAULT_BUFFER_SIZE = 10240; //10KB.
private String filePath;
 public void init() throws ServletException {

    this.filePath = "/files";
}

protected final void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
    System.out.println("In do get");

    //Get requested file by path info.
    String requestedFile = request.getPathInfo();

    //Check if file is actually supplied to the request URI.
    if (requestedFile == null) {
        //Do your thing if the file is not supplied to the request URI.
        //Throw an exception, or send 404, or show default/warning page, or just ignore it.
        response.sendError(HttpServletResponse.SC_NOT_FOUND); //404.
        return;
    }

    //Decode the file name (might contain spaces and on) and prepare file object.
    File file = new File(filePath, URLDecoder.decode(requestedFile, "UTF-8"));

    //Check if file actually exists in filesystem.
    if (!file.exists()) {
        //Do your thing if the file appears to be non-existing.
        //Throw an exception, or send 404, or show default/warning page, or just ignore it.
        response.sendError(HttpServletResponse.SC_NOT_FOUND); //404.
        return;
    }

    //Get content type by filename.
    String contentType = getServletContext().getMimeType(file.getName());

    //If content type is unknown, then set the default value.
    //For all content types, see: http://www.w3schools.com/media/media_mimeref.asp
    //To add new content types, add new mime-mapping entry in web.xml.
    if (contentType == null) {
        contentType = "application/octet-stream";
    }

    //Init servlet response.
    response.reset();
    response.setBufferSize(DEFAULT_BUFFER_SIZE);
    response.setContentType(contentType);
    response.setHeader("Content-Length", String.valueOf(file.length()));
    response.setHeader("Content-Disposition", "attachment; filename=\"" + file.getName() + "\"");

    //Prepare streams.
    BufferedInputStream input = null;
    BufferedOutputStream output = null;

    try {
        //Open streams.
        input = new BufferedInputStream(new FileInputStream(file), DEFAULT_BUFFER_SIZE);
        output = new BufferedOutputStream(response.getOutputStream(), DEFAULT_BUFFER_SIZE);

        //Write file contents to response.
        byte[] buffer = new byte[DEFAULT_BUFFER_SIZE];
        int length;
        while ((length = input.read(buffer)) > 0) {
            output.write(buffer, 0, length);
        }
    } finally {
        //Gently close streams.
        close(output);
        close(input);
    }
}

protected final void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
    System.out.println("In do post");

}


private static void close(Closeable resource) {
    if (resource != null) {
        try {
            resource.close();
        } catch (IOException e) {
            //Do your thing with the exception. Print it, log it or mail it.
            e.printStackTrace();
        }
    }
}

in web.xml die servlet-Eintrag ist wie folgt,

<servlet>
<description>
</description>
<display-name>FileServlet</display-name>
<servlet-name>FileServlet</servlet-name>
<servlet-class>com.mypackage.FileServlet</servlet-class>
</servlet>

<servlet-mapping>
<servlet-name>FileServlet</servlet-name>
<url-pattern>/file/*</url-pattern>
</servlet-mapping>

In Jsp habe ich img-tag wie folgt,

<img alt="Image" src="file/D:/uploads/img14.jsp" width="160" height="160"    class="img-thumbnail">

Ich glaube, ich machte Fehler im src-Attribut des img-tag, kann jemand sagen, wei ist der Fehler den ich hier gemacht .