Wie upload-Datei auf dem HTTP-server mit Hilfe der POST?

Ich versuche, upload-Datei auf dem HTTP-server mit Hilfe der POST, aber wenn ich Anrufe, es gibt Fehler zu
req.GetResponse(); im client-code

Der Remoteserver hat einen Fehler zurückgegeben: (405) Method not Allowed.

client-code

    public partial class _Default : System.Web.UI.Page
    {
        protected void Page_Load(object sender, EventArgs e)
        {
            string fileToUpload = Server.MapPath("~/Files/Ricky_Martin_Livin_la.mp3");
            string uploadUrl = "http://localhost/soundcheck/uploadfiles.aspx";
            //string uploadUrl = "http://10.0.2.2/musicapp/handle_upload.php";
            FileStream rdr = new FileStream(fileToUpload, FileMode.Open);
            HttpWebRequest req = (HttpWebRequest)WebRequest.Create(uploadUrl);
            req.Method = "PUT"; //you might use "POST"
            req.ContentLength = rdr.Length;
            req.AllowWriteStreamBuffering = true;

            Stream reqStream = req.GetRequestStream();

            byte[] inData = new byte[rdr.Length];

            //Get data from upload file to inData 
            int bytesRead = rdr.Read(inData, 0, int.Parse(rdr.Length.ToString()));

            //put data into request stream
            reqStream.Write(inData, 0, int.Parse(rdr.Length.ToString()));

            rdr.Close();
            req.GetResponse();

            //after uploading close stream 
            reqStream.Close();
        }
    }

Server-code

using System;
using System.Collections;
using System.IO;
using System.Data;
using System.Web;
using System.Text;
using System.Web.Security;

public partial class uploadfiles : System.Web.UI.Page
{
    protected void Page_Load(object sender, EventArgs e)
    {
        try
        {
            LogInFile("First");
            HttpFileCollection uploadFile = Request.Files;
            LogInFile("Second");
            if (uploadFile.Count > 0)
            {
                HttpPostedFile postedFile = uploadFile[0];
                LogInFile("Thrid");
                System.IO.Stream inStream = postedFile.InputStream;
                LogInFile("Forth");
                byte[] fileData = new byte[postedFile.ContentLength];
                LogInFile("Fifth");
                inStream.Read(fileData, 0, postedFile.ContentLength);
                LogInFile("Sixth");
                postedFile.SaveAs(Server.MapPath("Data") + "\\" + postedFile.FileName);
            }        
        }
        catch (Exception ex)
        { 
            StringBuilder sb = new StringBuilder();
            sb.AppendLine("Message : " +ex.Message);
            sb.AppendLine("Source : " + ex.Source);
            sb.AppendLine("StackTrace : " + ex.StackTrace);
            sb.AppendLine("InnerException : " + ex.InnerException);
            sb.AppendLine("ToString : " + ex.ToString());

            LogInFile(sb.ToString());
        }
    }
    public void LogInFile(string str)
    {
        StringBuilder sb = new StringBuilder();
        using (StreamReader sr = new StreamReader(Server.MapPath("Data") + "\\expfile.txt"))
        {            
            sb.AppendLine("= = = = = =");
            sb.Append(sr.ReadToEnd());
            sb.AppendLine();
            sb.AppendLine();
        }
        sb.AppendLine(str);
        using (StreamWriter outfile = new StreamWriter(Server.MapPath("Data") + "\\expfile.txt"))
        {
            outfile.Write(sb.ToString());
        }
    }

}

Im server-code, den ich Schreibe diese Protokolle zu verfolgen, wenn es irgendwelche Fehler oder Fehler in welcher Zeile.

InformationsquelleAutor Azhar | 2012-04-25
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