Einfache Postgresql libpq-code zu langsam ist?

Arbeitete ich auf postgresql mit libpq. Den unten angegebenen code nimmt eine Menge Zeit (Zeiten am Ende des Codes).

#include "stdafx.h"
#include <stdlib.h>
#include <libpq-fe.h>
#include <windows.h>

static void exit_nicely(PGconn *conn)
{
    PQfinish(conn);
    exit(1);
}

int _tmain(int argc, _TCHAR* argv[])
{
    const TCHAR *conninfo;
    PGconn     *conn;
    PGresult   *res;
    int nFields, i, j;

    if (argc > 1)
        conninfo = argv[1];
    else
        conninfo = _T("hostaddr=192.168.4.171 port=12345 dbname=mydb user=myname password=mypass");

    conn = PQconnectdb(conninfo);
    if (PQstatus(conn) != CONNECTION_OK)
    {
        fprintf(stderr, "Connection to database failed: %s",
                PQerrorMessage(conn));
        exit_nicely(conn);
    }

    /* Start a transaction block */
    res = PQexec(conn, "BEGIN");
    if (PQresultStatus(res) != PGRES_COMMAND_OK)
    {
        fprintf(stderr, "BEGIN command failed: %s", PQerrorMessage(conn));
        PQclear(res);
        exit_nicely(conn);
    }

    TCHAR szVal1[200];
    TCHAR szVal2[200];
    TCHAR szBuffer[200];

    TCHAR *paramValues[2];
    int paramLengths[2];
    int paramFormats[2] = {0,0};

    ExecStatusType eStatus;

    LARGE_INTEGER li;
    QueryPerformanceFrequency(&li);
    double dAppFreq = double(li.QuadPart)/1000.0;

    QueryPerformanceCounter(&li);
    LONGLONG siStartCounter = li.QuadPart;

    TCHAR szStmt[512] = {0};
    _tcscpy_s(szStmt, 512, _T("Insert50k"));
    Oid oidTypes[2] = {0,0};

    PGresult *pRes =    PQprepare(conn,
                        szStmt,
                        _T("insert into details values($1,$2);"),
                        2,
                        oidTypes);
    QueryPerformanceCounter(&li);
    LONGLONG siEndCounter = li.QuadPart;
    LONGLONG siLoop = 0;

    double dDiff = (siEndCounter - siStartCounter)/dAppFreq;
    printf("Prepared %.2lf\n", dDiff);

    for(int i=0; i<50000; i++)
    {
        _stprintf_s(szVal1, 200, _T("%d"), i);
        _stprintf_s(szVal2, 200, _T("Detail%d"), i);

        paramValues[0] = szVal1;
        paramValues[1] = szVal2;

        paramLengths[0] = _tcslen(szVal1);
        paramLengths[1] = _tcslen(szVal2);

        siStartCounter = siEndCounter;
        pRes = PQexecPrepared(conn,
                         szStmt,
                         2,
                         paramValues,
                         paramLengths,
                         paramFormats,
                         0);
        QueryPerformanceCounter(&li);
        siEndCounter = li.QuadPart;
        siLoop += (siEndCounter - siStartCounter);

        eStatus = PQresultStatus(res);
        if (!res ||  (eStatus != PGRES_COMMAND_OK) )
        {
            PQclear(res);
            exit_nicely(conn);
        } 
    }

    dDiff = siLoop/dAppFreq;
    printf("Inserted %.2lf\n", dDiff);

    siStartCounter = siEndCounter;


    _tcscpy_s(szBuffer,200, _T("select count(*) from programdetails;"));
    res = PQexec(conn, szBuffer);

    eStatus = PQresultStatus(res);
    if (!res ||  (eStatus != PGRES_TUPLES_OK) )
    {
        PQclear(res);
        exit_nicely(conn);
    }

    /* first, print out the attribute names */
    nFields = PQnfields(res);
    for (i = 0; i < nFields; i++)
        printf("%-15s", PQfname(res, i));
    printf("\n\n");

    /* next, print out the rows */
    for (i = 0; i < PQntuples(res); i++)
    {
        for (j = 0; j < nFields; j++)
            printf("%-15s", PQgetvalue(res, i, j));
        printf("\n");
    }

    QueryPerformanceCounter(&li);
    siEndCounter = li.QuadPart;
    dDiff = (siEndCounter - siStartCounter)/dAppFreq;
    printf("Printed %.2lf\n", dDiff);

    /* end the transaction */
    res = PQexec(conn, "COMMIT");
    PQclear(res);

    /* close the connection to the database and cleanup */
    PQfinish(conn);

    return 0;
}

Ein Beispiel für die Ausgabe (in MSEK):

Prepared 0.55
Inserted 5527.52
count

50000
Printed 7.58

Die Abfrage hier bereit ist, den ersten, und dann ausgeführt. Dieses einfache Montage dauert etwa 5,5 Sekunden. Gibt es eine bessere Möglichkeit, das gleiche zu tun oder mache ich etwas falsch hier?