Excel-makro text-Datei Lesen Wort für Wort und Schreibe jedes Wort auf eine neue Zelle in der gleichen Spalte

Referenz: http://www.experts-exchange.com/Software/Office_Productivity/Office_Suites/MS_Office/A_1480-How-to-Split-a-String-with-Multiple-Delimiters-in-VBA.html

Deine Frage enthält einige Teil

1.Lesen Sie txt-Datei in einen string (Excel string limit) ich habe versucht, erhalten eine Fehlermeldung "Out of String Space" , also ich hoffe, dass Ihre "Große" Datei nicht > 1G oder etwas

2.Teilen Sie Sie durch Tcl /tk-Trennzeichen

3.Ausgabe E-Mail pro Zeile

Sub Testing()
    Dim fname As String
    Dim sVal As String
    Dim count As Long
    Dim ws As Worksheet
    Set ws = Worksheets("Sheet2") 'Replace Sheet1 with the output sheet name you want
    fname = "H:\My Documents\a.txt"   'Replace the path with your txt file path
    sVal = OpenTextFileToString2(fname)
    Dim tmp As Variant
    tmp = SplitMultiDelims(sVal, ",; ", True)   ' Place the 2nd argument with the list of delimiter you need to use
    count = 0
    For i = LBound(tmp, 1) To UBound(tmp, 1)

         count = count + 1
         ws.Cells(count, 1) = tmp(i)  'output on the first column

    Next i
End Sub    


Function OpenTextFileToString2(ByVal strFile As String) As String
' RB Smissaert - Author
Dim hFile As Long
hFile = FreeFile
Open strFile For Input As #hFile
OpenTextFileToString2 = Input$(LOF(hFile), hFile)
Close #hFile
End Function


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' SplitMultiDelims by alainbryden
' This function splits Text into an array of substrings, each substring
' delimited by any character in DelimChars. Only a single character
' may be a delimiter between two substrings, but DelimChars may
' contain any number of delimiter characters. It returns a single element
' array containing all of text if DelimChars is empty, or a 1 or greater
' element array if the Text is successfully split into substrings.
' If IgnoreConsecutiveDelimiters is true, empty array elements will not occur.
' If Limit greater than 0, the function will only split Text into 'Limit'
' array elements or less. The last element will contain the rest of Text.
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Function SplitMultiDelims(ByRef Text As String, ByRef DelimChars As String, _
        Optional ByVal IgnoreConsecutiveDelimiters As Boolean = False, _
        Optional ByVal Limit As Long = -1) As String()
    Dim ElemStart As Long, N As Long, M As Long, Elements As Long
    Dim lDelims As Long, lText As Long
    Dim Arr() As String

    lText = Len(Text)
    lDelims = Len(DelimChars)
    If lDelims = 0 Or lText = 0 Or Limit = 1 Then
        ReDim Arr(0 To 0)
        Arr(0) = Text
        SplitMultiDelims = Arr
        Exit Function
    End If
    ReDim Arr(0 To IIf(Limit = -1, lText - 1, Limit))

    Elements = 0: ElemStart = 1
    For N = 1 To lText
        If InStr(DelimChars, Mid(Text, N, 1)) Then
            Arr(Elements) = Mid(Text, ElemStart, N - ElemStart)
            If IgnoreConsecutiveDelimiters Then
                If Len(Arr(Elements)) > 0 Then Elements = Elements + 1
            Else
                Elements = Elements + 1
            End If
            ElemStart = N + 1
            If Elements + 1 = Limit Then Exit For
        End If
    Next N
    'Get the last token terminated by the end of the string into the array
    If ElemStart <= lText Then Arr(Elements) = Mid(Text, ElemStart)
    'Since the end of string counts as the terminating delimiter, if the last character
    'was also a delimiter, we treat the two as consecutive, and so ignore the last elemnent
    If IgnoreConsecutiveDelimiters Then If Len(Arr(Elements)) = 0 Then Elements = Elements - 1

    ReDim Preserve Arr(0 To Elements) 'Chop off unused array elements
    SplitMultiDelims = Arr
End Function