TypeError: __init__() got an unexpected keyword argument 'Methode'

Gut,ich Schreibe ein Fläschchen Projekt ,aber wenn ich versuchte, Sie zu python manage.py

Die traceback-erzählte mir, dass:

Traceback (most recent call last):
  File "manage.py", line 5, in <module>
    from app import db,create_app
  File "/home/humbert/2017-sharing-backend/sharing/app/__init__.py", line 42, in <module>
    app.register_blueprint(main_blueprint, url_prefix='/main')
  File "/home/humbert/venv/local/lib/python2.7/site-packages/flask/app.py", line 64, in wrapper_func
    return f(self, *args, **kwargs)
  File "/home/humbert/venv/local/lib/python2.7/site-packages/flask/app.py", line 951, in register_blueprint
    blueprint.register(self, options, first_registration)
  File "/home/humbert/venv/local/lib/python2.7/site-packages/flask/blueprints.py", line 154, in register
    deferred(state)
  File "/home/humbert/venv/local/lib/python2.7/site-packages/flask/blueprints.py", line 173, in <lambda>
    s.add_url_rule(rule, endpoint, view_func, **options))
  File "/home/humbert/venv/local/lib/python2.7/site-packages/flask/blueprints.py", line 76, in add_url_rule
    view_func, defaults=defaults, **options)
  File "/home/humbert/venv/local/lib/python2.7/site-packages/flask/app.py", line 64, in wrapper_func
    return f(self, *args, **kwargs)
  File "/home/humbert/venv/local/lib/python2.7/site-packages/flask/app.py", line 1043, in add_url_rule
    rule = self.url_rule_class(rule, methods=methods, **options)
TypeError: __init__() got an unexpected keyword argument 'method'

Ich glaube, mein manage.py ist richtig,und ich kann nicht herausfinden, die Fehler.

die Fehler Teil des __init__.py ist, dass:

from .main import main as main_blueprint
app.register_blueprint(main_blueprint, url_prefix='/main')

from .auth import auth as auth_blueprint
app.register_blueprint(auth_blueprint, url_prefix="/auth")

from . import views

Ich brauche wirklich etwas Hilfe,Danke!

InformationsquelleAutor HumbertZhang | 2017-02-09