Wie man Land name

Ich verwendete den folgenden code, um die Liste der Kultur-Typ, ist Ihre Art und Weise auf, wie man nur den Namen des Landes?

Danke

        static void Main(string[] args)
       {

        StringBuilder sb = new StringBuilder();

        foreach (CultureInfo ci in CultureInfo.GetCultures(CultureTypes.SpecificCultures))
        {
            sb.Append(ci.DisplayName);
            sb.AppendLine();
        }
        Console.WriteLine(sb.ToString());
        Console.ReadLine();


    }

Beispiel-Ausgabe:

Spanisch (Puerto Rico)

Spanisch (Vereinigte Staaten)

InformationsquelleAutor der Frage xscape | 2010-09-07

  1. 3

    Gut, dieser reguläre Ausdruck scheint zu tun, den job in den meisten Fällen:

            var regex = new System.Text.RegularExpressions.Regex(@"([\w+\s*\.*]+\))");
        foreach (var item in CultureInfo.GetCultures(CultureTypes.SpecificCultures))
        {
            var match = regex.Match(item.DisplayName);
            string countryName = match.Value.Length == 0 ? "NA" : match.Value.Substring(0, match.Value.Length - 1);
            Console.WriteLine(countryName);
        }

    InformationsquelleAutor der Antwort Edgar Sánchez

  2. 48

    Können Sie die Name-Eigenschaft der CultureInfo-Bau einer RegionInfo. Dann können Sie die DisplayName-Eigenschaft.
    Versuchen:

    foreach (CultureInfo ci in CultureInfo.GetCultures(CultureTypes.SpecificCultures))
{
            var ri = new RegionInfo(ci.Name);
            Console.WriteLine(ri.DisplayName);
}

    InformationsquelleAutor der Antwort Eric MSFT

  3. 1
    //Build your normal dictionary as container
Dictionary<string, string> countryNames = new Dictionary<string, string>();
foreach (CultureInfo ci in CultureInfo.GetCultures(CultureTypes.SpecificCultures))
{
    RegionInfo ri = new RegionInfo(ci.Name);
    //Check if the ISO language code is already in your collection 
    //Because you don't want double entries in a country box because we had to use the culture info
    if (!countryNames.ContainsKey(ri.TwoLetterISORegionName))
    {
        countryNames.Add(ri.TwoLetterISORegionName.ToUpper(), ri.EnglishName);
    }
}
//Code for dictionary to dropdownlist transform can be written with your personal preference for symantics 
SelectList countryDropdown = new SelectList(countryNames.OrderBy(o => o.Value), "Key", "Value");

    Oder bereit für den Einsatz ohne Kommentare:

    Dictionary<string, string> countryNames = new Dictionary<string, string>();
foreach (CultureInfo ci in CultureInfo.GetCultures(CultureTypes.SpecificCultures))
{
    RegionInfo ri = new RegionInfo(ci.Name);
    if (!countryNames.ContainsKey(ri.TwoLetterISORegionName)) countryNames.Add(ri.TwoLetterISORegionName.ToUpper(), ri.EnglishName);
}
SelectList countryDropdown = new SelectList(countryNames.OrderBy(o => o.Value), "Key", "Value");

    InformationsquelleAutor der Antwort Lesage

  4. 0

    wäre dies, was Sie suchen:

            foreach (CultureInfo ci in CultureInfo.GetCultures(CultureTypes.SpecificCultures))
        {
            sb.Append(ci.EnglishName);
            sb.AppendLine();
        }

    InformationsquelleAutor der Antwort terrybozzio

  5. 0
         You will need to use following namespaces 

     using System.Configuration; 
     using System.Globalization;

    ///

        ///populate country name

    ///</summary>

    ///<param name="dropDown"></param>

    public static void GetCountryNames(DropDownList dropDown)

    {

        Hashtable h = new Hashtable();



        Dictionary<string, string> objDic = new Dictionary<string, string>();

        foreach (CultureInfo ObjCultureInfo in CultureInfo.GetCultures(CultureTypes.SpecificCultures))

        {

            RegionInfo objRegionInfo = new RegionInfo(ObjCultureInfo.Name);

            if (!objDic.ContainsKey(objRegionInfo.EnglishName))

            {

                objDic.Add(objRegionInfo.EnglishName, objRegionInfo.TwoLetterISORegionName.ToLower());

            }

        }



        SortedList<string, string> sortedList = new SortedList<string, string>(objDic);



        foreach (KeyValuePair<string, string> val in sortedList)

        {

            dropDown.Items.Add(new ListItem(val.Key, val.Key));

        }



        dropDown.Items.Insert(0, new ListItem("Select", "Select"));

        dropDown.Items.Insert(1, new ListItem("Other Country", "Other"));

    }

}

    InformationsquelleAutor der Antwort Jar Yit

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